25x^2-5x+4=0

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Solution for 25x^2-5x+4=0 equation:


Simplifying
25x2 + -5x + 4 = 0

Reorder the terms:
4 + -5x + 25x2 = 0

Solving
4 + -5x + 25x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
25 the coefficient of the squared term: 

Divide each side by '25'.
0.16 + -0.2x + x2 = 0

Move the constant term to the right:

Add '-0.16' to each side of the equation.
0.16 + -0.2x + -0.16 + x2 = 0 + -0.16

Reorder the terms:
0.16 + -0.16 + -0.2x + x2 = 0 + -0.16

Combine like terms: 0.16 + -0.16 = 0.00
0.00 + -0.2x + x2 = 0 + -0.16
-0.2x + x2 = 0 + -0.16

Combine like terms: 0 + -0.16 = -0.16
-0.2x + x2 = -0.16

The x term is -0.2x.  Take half its coefficient (-0.1).
Square it (0.01) and add it to both sides.

Add '0.01' to each side of the equation.
-0.2x + 0.01 + x2 = -0.16 + 0.01

Reorder the terms:
0.01 + -0.2x + x2 = -0.16 + 0.01

Combine like terms: -0.16 + 0.01 = -0.15
0.01 + -0.2x + x2 = -0.15

Factor a perfect square on the left side:
(x + -0.1)(x + -0.1) = -0.15

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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